(x+1)^2=(x+1)(2x+3)

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Solution for (x+1)^2=(x+1)(2x+3) equation:



(x+1)^2=(x+1)(2x+3)
We move all terms to the left:
(x+1)^2-((x+1)(2x+3))=0
We multiply parentheses ..
-((+2x^2+3x+2x+3))+(x+1)^2=0
We calculate terms in parentheses: -((+2x^2+3x+2x+3)), so:
(+2x^2+3x+2x+3)
We get rid of parentheses
2x^2+3x+2x+3
We add all the numbers together, and all the variables
2x^2+5x+3
Back to the equation:
-(2x^2+5x+3)
We get rid of parentheses
-2x^2-5x+(x+1)^2-3=0
We move all terms containing x to the left, all other terms to the right
-2x^2-5x+(x+1)^2=3

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